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Yang–MillsA QFT.ORG PROJECT

Why a lattice makes the theory definable

A finite lattice replaces a formal field integral by finitely many ordinary integrals over compact groups. Gauge invariance can be preserved exactly throughout this regularization.

Prerequisite: physical observables. The Haar measure bridge explains the integration measure.

By the end:

  • Write a finite-lattice expectation using normalized Haar measure.
  • Check gauge invariance with the site conventions.

Take a four-dimensional hypercubic lattice with spacing aa. To each positively oriented link from xx toward x+aμ^x+a\hat\mu, assign a matrix Ux,μ∈SU(N)U_{x,\mu}\in SU(N). This convention transports a column vector at the endpoint back to the base point. Reversing an orientation uses its inverse.

A lattice gauge transformation chooses Ωx∈SU(N)\Omega_x\in SU(N) at each site and acts by

Ux,μ⟼ΩxUx,μΩx+aμ^−1.U_{x,\mu}\longmapsto \Omega_xU_{x,\mu}\Omega_{x+a\hat\mu}^{-1}.

The elementary plaquette based at xx is

Ux,μν=Ux,μUx+aμ^,νUx+aν^,μ−1Ux,ν−1.U_{x,\mu\nu} =U_{x,\mu}U_{x+a\hat\mu,\nu} U_{x+a\hat\nu,\mu}^{-1}U_{x,\nu}^{-1}.

The matrices at interior endpoints cancel under a gauge transformation, leaving conjugation at xx. Therefore tr⁡Ux,μν\operatorname{tr}U_{x,\mu\nu} is gauge invariant. Larger closed loops work the same way.

Our link convention is compatible with Dμ=∂μ−iAμD_\mu=\partial_\mu-iA_\mu and Ux,μ≃e−iaAμ(x)U_{x,\mu}\simeq e^{-iaA_\mu(x)} for a smooth connection. Reversing the link convention changes this sign without changing the real traced plaquette action.

For the fundamental representation, use

SW[U]=β∑p(1−1NRe⁡tr⁡Up),β=2Ng02.S_W[U]=\beta\sum_p \left(1-\frac1N\operatorname{Re}\operatorname{tr}U_p\right), \qquad \beta=\frac{2N}{g_0^2}.

The sum counts each elementary plaquette once with a chosen orientation. The normalized expectation is

⟨O⟩a,L=1Za,L∫∏ℓdUℓ O[U] e−SW[U].\langle\mathcal O\rangle_{a,L} =\frac{1}{Z_{a,L}} \int\prod_{\ell}dU_\ell\, \mathcal O[U]\,e^{-S_W[U]}.

Each dUℓdU_\ell is normalized Haar measure, invariant under left and right multiplication. On a finite lattice the configuration space is a finite product of compact groups. The action is continuous and bounded; its exponential is strictly positive. Consequently 0<Za,L<∞0<Z_{a,L}<\infty.

This is an actual finite-dimensional definition, not an instruction to interpret an undefined DA\mathcal DA. Gauge-invariant expectations can be evaluated without first fixing a gauge. Wilson’s original formulation is the foundational source.

Recover the classical continuum expression

Section titled “Recover the classical continuum expression”

For a smooth field, expanding a small plaquette gives

Ux,μν=1−ia2Fμν−a42Fμν2+derivative and higher-order terms.U_{x,\mu\nu}=1-ia^2F_{\mu\nu} -\frac{a^4}{2}F_{\mu\nu}^2 +\text{derivative and higher-order terms}.

The tracelessness of FF removes the linear trace. At leading order,

1−1NRe⁡tr⁡Ux,μν=a42Ntr⁡Fμν2+⋯ .1-\frac1N\operatorname{Re}\operatorname{tr}U_{x,\mu\nu} =\frac{a^4}{2N}\operatorname{tr}F_{\mu\nu}^2+\cdots.

Substitute β=2N/g02\beta=2N/g_0^2 and convert the site sum to an integral:

SW⟶1g02∫d4x∑μ<νtr⁡Fμν2=12g02∫d4x tr⁡FμνFμν.S_W\longrightarrow \frac{1}{g_0^2}\int d^4x\sum_{\mu<\nu} \operatorname{tr}F_{\mu\nu}^2 =\frac{1}{2g_0^2}\int d^4x\, \operatorname{tr}F_{\mu\nu}F_{\mu\nu}.

The factor of two in the final expression comes from counting both (μ,ν)(\mu,\nu) and (ν,μ)(\nu,\mu).

This calculation explains the choice of lattice action. It does not prove the quantum continuum limit: typical quantum fields are not smooth configurations to which a naive pointwise expansion can be uniformly applied.

If the lattice has NsN_s sites along each spatial direction, its physical side length is L=NsaL=N_sa. A correlation length can be measured either in lattice sites, ξlatt\xi_{\mathrm{latt}}, or in physical units, ξphys=aξlatt\xi_{\mathrm{phys}}=a\xi_{\mathrm{latt}}.

Decreasing aa with fixed NsN_s shrinks the physical box. Increasing NsN_s with fixed aa removes the volume cutoff but leaves the ultraviolet cutoff. A continuum, infinite-volume calculation has to control both.

Likewise, a Wilson-loop area in plaquette units differs from its physical area by a factor a2a^2. A string tension in lattice units must be divided by a2a^2 to obtain the corresponding physical quantity.

Whenever a paper quotes a lattice mass, length, or coupling, write its convention next to the number. Comparing two calculations before this translation can create an apparent disagreement that is only a difference of units or normalization.

We have a finite regulated probability measure, exact gauge invariance, and well-defined bounded loop observables. These are substantial achievements. The remaining work includes the continuum limit, the infinite-volume limit, physical reconstruction, and spectral estimates.

For a construction of the limiting theory, regularized observables must also be chosen and renormalized appropriately. Lüscher’s Wilson-flow paper provides an important example of useful gauge-invariant quantities and scales.

Multiply the four transformed links around a plaquette. What happens to the gauge matrices?

Hint. Adjacent endpoint factors cancel.

Solution. The product becomes ΩxUx,μνΩx−1\Omega_xU_{x,\mu\nu}\Omega_x^{-1}. Cyclicity then makes its trace invariant.

An initial lattice has Ns=32N_s=32 and spacing aa. Halve aa while keeping the same physical box. What must happen to NsN_s?

Hint. Keep NsaN_sa fixed.

Solution. Increase NsN_s to 6464. In four dimensions an isotropic lattice then contains sixteen times as many sites, before considering any additional sampling cost.

The transfer matrix and physical time develops this lesson without adding a prerequisite to the next lesson.

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